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firefighting
Firefighting device for smooth fields/ grasslands | |
An idea to fight fires in a large grasslands/smooth landscape grasslands and shrub area.
A suitable truck carrying a large roll of conveyor belt, say approx 3 to 4 metres wide and 10 mm thick. This belt can also be made of wire mesh impregnated into rubber and can contain flame retardant agent.
The
idea is to anchor the belt on on end of the field and drive forward with the truck(not too fast obviously)and then the belt will roll down onto the field, depressing the grass to block the path of the fire.
Four wheeler motorcycles or small pickups can be used to ride on top of the belt an thus depressing the grass or shrubs further.These vehicles can also carry water tanks and nozzles to wet the field around the edges of the belt and to act as fire patrol.
The roll diameter of the wound up belt:
D= SQR[(4/pi * t)*(L+2d)
Where
D =Roll diameter of the wound up belt(m)
t =Thickness of belt(m)
L =Length of belt(m)
d =Diameter of the roller on which the belt is wound up(m):
Here's my take on it for rougher terrain
Borate_20Bouncing_20Bettys
[normzone, Jan 30 2009]
infosharebackyard
http://569142087400...UHZcNmXdHBYsA%3D%3D
firefight [novaris, Feb 02 2009]
[link]
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This idea is a total wet blanket. + |
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Novaris, bring me some math, or maths if you are of that ilk, discussing the diameter of a roll of your belting. Each turn increases thickness by 20 mm but you get more length for each subsequent turn. I am thinking this will be a big roll. |
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A typical conveyor belt calc: |
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The roll diameter of the wound up belt:
D= SQR[(4/pi * t)*(L+2d)
Where:
D =Roll diameter of the wound up belt(m)
t =Thickness of belt(m)
L =Length of belt(m)
d =Diameter of the roller on which the belt is wound up(m): |
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Is that the correct formula? |
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For instance:
I have a roll of 400 metres in length and 8 mm in thickness: |
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L = 400 m
t = .008 m
d = .5 m |
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